首页

欢迎

 

Welcome

欢迎来到这里, 这是一个学习数学、讨论数学的网站.

转到问题

请输入问题号, 例如: 2512

IMAGINE, THINK, and DO
How to be a scientist, mathematician and an engineer, all in one?
--- S. Muthu Muthukrishnan

Local Notes

Local Notes 是一款 Windows 下的笔记系统.

Local Notes 下载

Sowya

Sowya 是一款运行于 Windows 下的计算软件.

详情

下载 Sowya.7z (包含最新版的 Sowya.exe and SowyaApp.exe)


注: 自 v0.550 开始, Calculator 更名为 Sowya. [Sowya] 是吴语中数学的发音, 可在 cn.bing.com/translator 中输入 Sowya, 听其英语发音或法语发音.





注册

欢迎注册, 您的参与将会促进数学交流. 注册

在注册之前, 或许您想先试用一下. 测试帐号: usertest 密码: usertest. 请不要更改密码.


我制作的 slides

Problem

随机显示问题

Problèmes d'affichage aléatoires

概率统计 >> 概率论
Questions in category: 概率论 (Probability).

泊松过程(Poisson process)

Posted by haifeng on 2020-04-07 08:09:41 last update 2020-04-07 08:09:41 | Answers (0)


泊松过程(Poisson process)

A very important application of the Poisson distribution arises in connection with the occurrence of events of a particular type over time. As an example, suppose that starting from a time point that we label $t=0$, we are interested in counting the number of radioactive pulses(放射性脉冲) recorded by a Geiger counter(盖革计数器). We make the following assumptions about the way in which pulses occur:

  • 1. There exists a parameter $\alpha > 0$ such that for any short time interval of length $\Delta t$, the probability that exactly one pulse is receive is $\alpha\cdot\Delta t+o(\Delta t)$.
  • 2. The probability of more than one pulse being received during $\Delta t$ is $o(\Delta t)$ [which, along with Assumption 1, implies that the probability of no pulses during $\Delta t$ is $1-\alpha\cdot\Delta t-o(\Delta t)$].
  • 3. The number of pulses received during the time interval $\Delta t$ is independent of the number received prior to this time interval.
     

Informally, Assumption 1 says that, for a short interval of time, the probability of receiving a single pulse is approximately proportional to the length of the time interval, where $\alpha$ is the constant of proportionality.

Now let $P_k(t)$ denote the probability that $k$ pulses will be received by the counter during any particular time interval of length $t$.

Proposition. $P_k(t)=\frac{e^{-\alpha t}\cdot(\alpha t)}{k!}$, so that the number of pulses during a time interval of length $t$ is a Poisson rv with parameter $\lambda=\alpha t$. The expected number of pulses during any such time interval is then $\alpha t$, so the expected number during a unit interval of time is $\alpha$.
 


References:

The above content in English is copied from the following book:

《Probability and Statistics For Engineering and The Sciences》(Fifth Edtion) P.131
Author: Jay L. Devore

Section 5 of Chapter 3.