Answer

问题及解答

从 $\mathbb{N}-\{1\}$ 中删去 2,3,5 的倍数, 得到数列 $\{u_n\}_{n=1}^{+\infty}$. 求 $d_n=u_{n+1}-u_n$.

Posted by haifeng on 2011-06-16 12:44:36 last update 0000-00-00 00:00:00 | Edit | Answers (0)

$u_n$:
7,11,13,17,19,23,29,31,37,41,43,47,49,53,59,61,67,71,73,77,79,83,89,91,97,101
$d_n$:
4 2 4 2 4 6 2 6 | 4 2 4 2 4 6 2 6 | 4 2 4 2 4 6 2 6 | 4 ...