证明: $H_2(\mathbb{C}P^2,\mathbb{Z})\cong\mathbb{Z}$.
证明: $H_2(\mathbb{C}P^2,\mathbb{Z})\cong\mathbb{Z}$.
Answer
证明: $H_2(\mathbb{C}P^2,\mathbb{Z})\cong\mathbb{Z}$.