求解不定方程 $x+2y+3z=4$.
>> IndefiniteEquation(1,2,3;4)
in> IndefiniteEquation(1,2,3;4)
Solve the indefinite equation :
1*X1+2*X2+3*X3 = 4
X3=4-X1-2u1
---------------
X2 = -1*X3+u1
X1 = +X1
------------------------
Answer
>> IndefiniteEquation(1,2,3;4)
in> IndefiniteEquation(1,2,3;4)
Solve the indefinite equation :
1*X1+2*X2+3*X3 = 4
X3=4-X1-2u1
---------------
X2 = -1*X3+u1
X1 = +X1
------------------------