Posted by haifeng on 2023-10-11 23:28:21 last update 2023-10-11 23:28:21 | Edit | Answers (1)
求极限 limx→0secx−cosxx2.
1
Posted by haifeng on 2023-10-11 23:33:09
limx→0secx−cosxx2=limx→01cosx(1−cos2x)x2=limx→0sin2xx2=limx→0x2x2=1.