Posted by haifeng on 2014-09-21 15:57:56 last update 2014-12-28 22:06:22 | Answers (2) | 收藏
求极限
limn→∞1n∑k=1nsinkn.
limn→∞(sinπnn+1+sin2πnn+12+⋯+sinπn+1n).