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Questions in category: 极限 (Limit).

求极限 limn1nk=1nsink/n.

Posted by haifeng on 2014-09-21 15:57:56 last update 2014-12-28 22:06:22 | Answers (2) | 收藏


求极限

limn1nk=1nsinkn.


limn(sinπnn+1+sin2πnn+12++sinπn+1n).