Posted by haifeng on 2020-03-25 16:26:38 last update 2020-03-25 16:26:57 | Answers (1) | 收藏
(a) Show that $b(x;n,1-p)=b(n-x;n,p)$.
(b) Show that $B(x;n,1-p)=1-B(n-x-1;n,p)$. [Hint: At most $x$ $S$'s is equivalent to at least $(n-x)$ $F$'s.]
