Posted by haifeng on 2023-03-18 09:17:47 last update 2023-03-18 09:18:34 | Answers (1) | 收藏
令 $I(\alpha)=\displaystyle\int_0^{\frac{\pi}{2}}\dfrac{1}{1+\tan^{\alpha}x}\mathrm{d}x$, 求 $I'(\alpha)$.
