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分析 >> 数学分析 >> 微分中值定理
Questions in category: 微分中值定理 (Differential mean value theorem).

设 $\alpha,\beta\in(0,\frac{\pi}{2})$, 且 $\alpha\neq\beta$, 证明: $1 < \frac{\alpha\cos\beta-\beta\cos\alpha}{\alpha-\beta} < \frac{\pi}{2}$.

Posted by haifeng on 2022-11-10 14:29:26 last update 2022-11-10 14:29:26 | Answers (1) | 收藏


设 $\alpha,\beta\in(0,\frac{\pi}{2})$, 且 $\alpha\neq\beta$, 证明:

\[1 < \frac{\alpha\cos\beta-\beta\cos\alpha}{\alpha-\beta} < \frac{\pi}{2}.\]