问题

分析 >> 数学分析 >> 多元函数
Questions in category: 多元函数 (Multivariate functions).

证明在球坐标系下, 拉普拉斯算子 $\Delta=\frac{\partial^2}{\partial x^2}+\frac{\partial^2}{\partial y^2}+\frac{\partial^2}{\partial z^2}$ 可写为 $\frac{1}{r^2}\frac{\partial}{\partial r}(r^2\frac{\partial}{\partial r})+\frac{1}{r^2\sin\theta}\frac{\partial}{\partial\theta}(\sin\theta\frac{\partial}{\partial\theta})+\frac{1}{r^2\sin^2\theta}\frac{\partial^2}{\partial\phi^2}$.

Posted by haifeng on 2026-06-29 21:20:36 last update 2026-06-29 21:22:05 | Answers (1) | 收藏


证明在球坐标系下, 拉普拉斯算子 $\Delta=\frac{\partial^2}{\partial x^2}+\frac{\partial^2}{\partial y^2}+\frac{\partial^2}{\partial z^2}$ 可写为

\[
\frac{1}{r^2}\frac{\partial}{\partial r}(r^2\frac{\partial}{\partial r})+\frac{1}{r^2\sin\theta}\frac{\partial}{\partial\theta}(\sin\theta\frac{\partial}{\partial\theta})+\frac{1}{r^2\sin^2\theta}\frac{\partial^2}{\partial\phi^2}.
\]

这里

\[
\begin{cases}
x=r\sin\theta\cos\phi,\\
y=r\sin\theta\sin\phi,\\
z=r\cos\theta,
\end{cases}
\]

其中 $\theta\in[0,\pi]$, $\phi\in[0,2\pi]$.