Questions in category: 极限 (Limit)
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91. $\lim_{u\rightarrow 0^+}\ln(1-u)\ln u=?$

Posted by haifeng on 2013-06-21 10:38:39 last update 2013-06-21 10:55:55 | Answers (0) | 收藏


$\lim_{u\rightarrow 0^+}\ln(1-u)\ln u=?$


首先不妨先做个观察, 令 $t=\frac{1}{u}$, $t\rightarrow +\infty$, 从而

\[
\ln(1-u)\ln u=\ln(1-\frac{1}{t})\ln\frac{1}{t}=-\ln(1-\frac{1}{t})\ln t < -\ln(1-\frac{1}{t})\cdot t=\ln(1+\frac{1}{-t})^{-t}
\]

\[
\lim_{t\rightarrow +\infty}\ln(1+\frac{1}{-t})^{-t}=1
\]

于是, 当 $t\rightarrow +\infty$ 时,

\[
-\ln(1-\frac{1}{t})\ln t=-\ln(1-\frac{1}{t})\cdot t\cdot \frac{\ln t}{t}\rightarrow 0.
\]


推论: $\lim_{u\rightarrow 1^-}\ln(1-u)\ln u=0$.

92. 求 $\lim\limits_{n\rightarrow +\infty}\frac{(2n-1)!!}{(2n)!!}$.

Posted by haifeng on 2012-05-29 15:40:53 last update 2016-02-03 22:35:12 | Answers (1) | 收藏


\[\lim\limits_{n\rightarrow +\infty}\frac{(2n-1)!!}{(2n)!!}\]


Remark

实际上, 有更详细的 Wallis 公式 (见问题702)

\[\frac{\pi}{2}=\lim_{n\rightarrow+\infty}\biggl[\frac{(2n)!!}{(2n-1)!!}\biggr]^2\frac{1}{2n+1}\]

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